Didn't the Ravens hire a numbers guru. Maybe he could chime in. :)
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Didn't the Ravens hire a numbers guru. Maybe he could chime in. :)
I think some of us are bored,something to do :laugh:
I just use something like Sketchup,it does all the figuring.
but I used the 54 yds distance.
Comes up with an arc of 202' 3 3/8".
(a little over 67 1/3 yds.)
I dunno,I could have messed it up.
http://farm9.staticflickr.com/8333/8...1956f739_c.jpg
http://farm9.staticflickr.com/8217/8...7c74e7da_c.jpg
http://farm9.staticflickr.com/8511/8...11612bc6_c.jpg
OMG Thread of the WEEK. LOL
So assuming the vertical displacement is negligible, we have a distance traveled of 49 meters in a time of 3.2 seconds.
We can calculate vertical velocity by using
0 = (initial velocity)(3.2) + 1/2 ( -9.8) (3.2^2)
This comes out to an initial vertical velocity of 15.68 m/s
We can then approximate max height using
0 = 15.68^2 - 2 (-9.8)(max height)
This gives us a max height of ~ 12.544 meters or about 36 feet
Initial horizontal velocity can be calculated using
49 = x(3.2) + 1/2* -.1 * (3.2^2)
This gives us an initial horizontal velocity of approximately 15.475 m/s
Using the calculated stuff here, we can use the following:
Integral from 0 to 3.2 of
sqrt((15.47 - .1t)^2 + (15.68 - 9.8t)^2)
Which gives us an arc length of 74.551 meters, or approximately 81 yards.
Pretty awesome. Note these are rough figures, since we can't really be completely precise with the information we have
BaltimoreBoy - Do yourself a favor and email that to ESPN/sports science with emphasis on whether Moore could have made that play. That would be a sweet segment and I can't recall an episode where they focused on ball distance / height.
I'm not sure if my calculations are off or theirs are, but we're getting 2 different values.
Also:
http://i.imgur.com/L2Tsr.jpg
This thread will end poverty and end all wars.